Got A Thermal Science Question For Ya....

I know we have a talented bunch, so thought I'd give this a go here to see who bites...


If you take away 5.2 x 10^6 (10 to the 6th power) Joules of heat from 1.5 kg of water vapor at 100 degrees Celcius, at what state would it become and what temperature would it be?

Specific Heat Capacity for water is 4186 j/(kg x C)
Specific Heat Capacity for ice 2.00 x 10^3 j/(kg x C)
Latent Heat of Fusion is 33.5 x 10^4 j/(kg)
Latent Heat of Evaporization is 22.6 x 10^5 j/(kg)

The water vapor must turn from a vapor to a liquid and if necessary to ice depending how much heat is taken out.

TIMES UP!!!!

First do the heat from condensing to water, then temperature from 100 to 0 degrees, then changing from water to ice, then the final temperature is based on whatever is left.


1.5 x 22.6x10^5 = 33.9 x 10^5 steam to water

4186 x 1.5 x 100 = 627900 100 degrees to 0 degrees

1.5 x 33.5x10^4 = 50.25 x 10^4 water to ice

total so far... 4520400 joules

1.5 x T x 2x10^3


5.2 x 10^6 = 5200000J - 4520400J = 679600 J / (1.5 x 2x10^3)

T = 226.53 below zero


ICE.

nerd.

Domino wrote:

nerd.

uhh yeah i F1 that.

F2

Go color....